Monday, November 27, 2023

# M15 Concrete Ratio ( 1:2:4 ) : Materials Calculation For Preparing M15 Concrete

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M15 concrete ratio is 1:2:4. It indicates the cement:sand: aggregate ratio. It simply means that if 1 kg cement is used for making Concrete, you should use 2 kg sand and 4 kg aggregate. ( i.e. 1 part cement: 2 parts sand: 4 parts aggregate )

✔ In M15 concrete,

“M” stands for Mix ratio of cement:sand: aggregate  &  “15 “Stands for Compressive Strength @ 28 Days in N/mm².

✔ M15 Concrete is nominal Concrete that can be skillfully prepared using Indian Standard 10262(2009).

✔ Normally, about 38% of water is required for the complete hydration of Concrete.

As per IS 10262(2019) for nominal mix ( i.e. M10, M15…, M25);  the w/c ratio varies from 0.4 to 0.6.

For M15 Concrete, commonly w/c ratio of 0.50 to 0.55 is used.

### 1. Table1: M15 Concrete Ratio – Overview

 Code Indian Standard 10262(2009). Ratio 1:2:4 Compressive Strength 15 MPa { Note: MPa = N/mm²} Uses Used in general-purpose work or temporary structures.Mostly used in the construction of parking, landscaping, gardening, etc. Grade Category Normal Grade ( Nominal Mix ) Required  Water Cement Ratio a. For high-quality concrete works; 0.50 w/c ratio is specified.b. Minimum water-cement ratio: 0.50c. Maximum water-cement ratio: 0.55

### 2. M15 Concrete Ratio Uses

This concrete grade is commonly used for small temporary constructions. Some common uses of the M15 Concrete Ratio are:

✔ Used in the construction of general RCC works ( Such as slabs, beams, columns, etc. )

✔ Used in general-purpose work or temporary structures.

✔ Mostly used in the construction of parking, landscaping, gardening, etc.

### 3. Cement Sand Aggregate Calculation For 1 m³ M15 Concrete Ratio

 Things To Know!!Density of = 1440 kg/m3Density of = 1450-1500 Kg/m3Density of Aggregate = 1450-1550 Kg/m3Weight of Cement in 1 Bag = 50 KgVolume of 1 Bag of Cement in Cubic meter = 0.03472 m3

Now, Taking

Grade of Concrete = M15 Concrete

Mix Ratio = 1:2:4

Total sum of ratio =1+2+4 =7

Wet volume of Concrete = 1 m3.

To get dry volume, wet volume increased by 54%

Dry volume of concrete = 1 + 0.54 = 1.54 m³

#### i. Cement Quantity Calculation

Quantity of cement = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 1/7 ) * 1.54

=  0.22 m³

Cement in kg = volume of cement * density of cement

= 0.22 * 1440

= 316.8 kg

#### ii. Sand Quantity Calculation

Quantity of sand = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 2/7 ) * 1.54

=  0.44 m³

#### iii. Aggregate Quantity Calculation

Quantity of = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 4/7 ) * 1.54

=  0.88 m³

#### iv. Water Calculation

For inferior-quality concrete: W/C ratio = 0.55

For superior-quality concrete: W/C ratio = 0.50

Minimum amount of water required per m³ = 0.50 * 316.8 = 158.4 kg

Maximum amount of water required per m³ = 0.55 * 316.8 = 174.24 kg

### 4. References

1. IS 10262 (2009): Code

 Verified Article By Er. Madhu Krishna Poudel

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Er. Madhu Krishna Poudel ( Founder )
Madhu Krishana Poudel is a distinguished Civil Engineer with extensive experience in site supervision, estimation, and AutoCAD 2D and 3D design. Holding a Bachelor's degree in Civil Engineering from Pokhara University, his work and expertise have earned recognition in reputable sources such as USA Today, Time, Wikipedia, and TheRichest, establishing his credibility and trustworthiness in the construction industry.
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