# M15 Concrete Ratio ( 1:2:4 ) : Materials Calculation For Preparing M15 Concrete

M15 concrete ratio is 1:2:4. It indicates the cement:sand: aggregate ratio. It simply means that if 1 kg cement is used for making Concrete, you should use 2 kg sand and 4 kg aggregate. ( i.e. 1 part cement: 2 parts sand: 4 parts aggregate )

✔ In M15 concrete,

“M” stands for Mix ratio of cement:sand: aggregate  &  “15 “Stands for Compressive Strength @ 28 Days in N/mm².

✔ M15 Concrete is nominal Concrete that can be skillfully prepared using Indian Standard 10262(2009).

✔ Normally, about 38% of water is required for the complete hydration of Concrete.

As per IS 10262(2019) for nominal mix ( i.e. M10, M15…, M25);  the w/c ratio varies from 0.4 to 0.6.

For M15 Concrete, commonly w/c ratio of 0.50 to 0.55 is used.

### 1. Table1: M15 Concrete Ratio – Overview

 Code Indian Standard 10262(2009). Ratio 1:2:4 Compressive Strength 15 MPa { Note: MPa = N/mm²} Uses Used in general-purpose work or temporary structures.Mostly used in the construction of parking, landscaping, gardening, etc. Grade Category Normal Grade ( Nominal Mix ) Required  Water Cement Ratio a. For high-quality concrete works; 0.50 w/c ratio is specified.b. Minimum water-cement ratio: 0.50c. Maximum water-cement ratio: 0.55

### 2. M15 Concrete Ratio Uses

This concrete grade is commonly used for small temporary constructions. Some common uses of the M15 Concrete Ratio are:

✔ Used in the construction of general RCC works ( Such as slabs, beams, columns, etc. )

✔ Used in general-purpose work or temporary structures.

✔ Mostly used in the construction of parking, landscaping, gardening, etc.

### 3. Cement Sand Aggregate Calculation For 1 m³ M15 Concrete Ratio

 Things To Know!!Density of = 1440 kg/m3Density of = 1450-1500 Kg/m3Density of Aggregate = 1450-1550 Kg/m3Weight of Cement in 1 Bag = 50 KgVolume of 1 Bag of Cement in Cubic meter = 0.03472 m3

Now, Taking

Grade of Concrete = M15 Concrete

Mix Ratio = 1:2:4

Total sum of ratio =1+2+4 =7

Wet volume of Concrete = 1 m3.

To get dry volume, wet volume increased by 54%

Dry volume of concrete = 1 + 0.54 = 1.54 m³

#### i. Cement Quantity Calculation

Quantity of cement = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 1/7 ) * 1.54

=  0.22 m³

Cement in kg = volume of cement * density of cement

= 0.22 * 1440

= 316.8 kg

#### ii. Sand Quantity Calculation

Quantity of sand = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 2/7 ) * 1.54

=  0.44 m³

#### iii. Aggregate Quantity Calculation

Quantity of = (Own Ratio/ Total sum of ratio) * Dry Volume

= ( 4/7 ) * 1.54

=  0.88 m³

#### iv. Water Calculation

For inferior-quality concrete: W/C ratio = 0.55

For superior-quality concrete: W/C ratio = 0.50

Minimum amount of water required per m³ = 0.50 * 316.8 = 158.4 kg

Maximum amount of water required per m³ = 0.55 * 316.8 = 174.24 kg

### 4. References

1. IS 10262 (2009): Code

 Verified Article By Er. Madhu Krishna Poudel
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