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M10 concrete ratio is 1:3:6. It indicates the cement:sand: aggregate ratio. It simply means that if 1 kg cement is used for making Concrete, you should use 3 kg sand and 6 kg aggregate. ( i.e., 1 part cement: 3 parts sand: 6 parts aggregate )
✔ In M10 concrete, “M” stands for Mix ratio of cement:sand: aggregate & “10 “Stands for Compressive Strength @ 28 Days in N/mm².
✔ M10 Concrete is nominal concrete that can be prepared using Indian Standard 10262(2009).
✔ Normally, about 38% of water is required for the complete hydration of Concrete.
As per IS 10262(2019) for nominal mix ( i.e. M10, M15…, M25); the w/c ratio varies from 0.4 to 0.6.
For M10 Concrete, commonly w/c ratio of 0.55 to 0.60 is used.
1. Table1: M10 Concrete Ratio – Overview
| Code | Indian Standard 10262(2009). |
| Ratio | 1:3:6 |
| Compressive Strength | 10 MPa { Note: MPa = N/mm²} |
| Uses | Used in general-purpose work or temporary structures. Mostly used in the construction of parking, landscaping, gardening, etc. |
| Grade Category | Normal Grade ( Nominal Mix ) |
| Required Water Cement Ratio | a. For high-quality concrete works; 0.55 w/c ratio is specified. b. Minimum water-cement ratio: 0.55 c. Maximum water-cement ratio: 0.60
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2. M10 Concrete Ratio Uses
This concrete grade is commonly used for small temporary constructions. Some common uses of the M10 Concrete Ratio are:
✔ Used in the construction of mass concrete and foundations of less importance.
✔ Used in general-purpose temporary structures.
✔ Mostly used in the construction of parking, landscaping, gardening, etc.
3. Cement Sand Aggregate Calculation For 1 m³ M10 Concrete Ratio
| Things To Know!! Density of Cement = 1440 kg/m3 Density of Sand = 1450-1500 Kg/m3 Density of Aggregate = 1450-1550 Kg/m3 Weight of Cement in 1 Bag = 50 Kg Volume of 1 Bag of Cement in Cubic meter = 0.03472 m3 |
Now, Taking
Grade of Concrete = M10 Concrete
Mix Ratio = 1:3:6
Total sum of ratio =1+3+6 =10
Wet volume of Concrete = 1 m3.
To get dry volume, wet volume increased by 54%
Dry volume of concrete = 1 + 0.54 = 1.54 m³
i. Cement Quantity Calculation
Quantity of cement = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 1/10 ) * 1.54
= 0.154 m³
Cement in kg = volume of cement * density of cement
= 0.154 * 1440
= 221.76 kg
ii. Sand Quantity Calculation
Quantity of sand = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 3/10 ) * 1.54
= 0.462 m³
iii. Aggregate Quantity Calculation
Quantity of aggregate = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 6/10 ) * 1.54
= 0.924 m³
iv. Water Calculation
For inferior-quality concrete: W/C ratio = 0.60
For superior-quality concrete: W/C ratio = 0.55
Minimum amount of water required per m³ = 0.55 * 221.76 = 121.968 kg
Maximum amount of water required per m³ = 0.60 * 221.76 = 133.056 kg
( 1 kg of water is equivalent to 1 L of water.)
4. References |
| Read Also: Grades of Concrete |
| Verified Article By Er. Madhu Krishna Poudel |
