M10 Concrete Ratio (1:3:6 ) : Materials Calculation For Preparing M10 Concrete

FactTopicsM10 Concrete Ratio (1:3:6 ) : Materials Calculation For Preparing M10 Concrete
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M10 concrete ratio is 1:3:6. It indicates the cement:sand: aggregate ratio. It simply means that if 1 part cement is used for making Concrete, you should use 3 parts sand and 6 parts aggregate by volume.

 ✔ In M10 concrete, “M” stands for Mix ratio of cement:sand: aggregate  &  “10 “Stands for Compressive Strength @ 28 Days in N/mm². ✔ M10 Concrete is nominal concrete that can be prepared using Indian Standard 10262(2009). ✔ Normally, about 38% of water is required for the complete hydration of Concrete. As per IS 10262(2019) for nominal mix ( i.e. M10, M15…, M25);  the w/c ratio varies from 0.4 to 0.6. For M10 Concrete, commonly w/c ratio of 0.55 to 0.60 is used.  


 

  1. Table1: M10 Concrete Ratio – Overview  

 

CodeIndian Standard 10262(2009).
Ratio1:3:6
Compressive Strength10 MPa { Note: MPa = N/mm²}
Uses  Used in general-purpose work or temporary structures. Mostly used in the construction of parking, landscaping, gardening, etc.
Grade CategoryNormal Grade ( Nominal Mix )
Required  Water Cement Ratio   a. For high-quality concrete works; 0.55 w/c ratio is specified. b. Minimum water-cement ratio: 0.55 c. Maximum water-cement ratio: 0.60  

 


 

  2. M10 Concrete Ratio Uses  

This concrete grade is commonly used for small temporary constructions. Some common uses of the M10 Concrete Ratio are:   m25 grade concrete ratio   ✔ Used in the construction of mass concrete and foundations of less importance. ✔ Used in general-purpose temporary structures. ✔ Mostly used in the construction of parking, landscaping, gardening, etc.  


 

  3. Cement Sand Aggregate Calculation For 1 m³ M10 Concrete Ratio  

Things To Know!! Density of Cement = 1440 kg/m3 Density of Sand = 1450-1500 Kg/m3 Density of Aggregate = 1450-1550 Kg/m3 Weight of Cement in 1 Bag = 50 Kg Volume of 1 Bag of Cement in Cubic meter = 0.03472 m3

  Now, Taking Grade of Concrete = M10 Concrete Mix Ratio = 1:3:6 Total sum of ratio =1+3+6 =10 Wet volume of Concrete = 1 m3. To get dry volume, wet volume increased by 54% Dry volume of concrete = 1 + 0.54 = 1.54 m³  

i. Cement Quantity Calculation

Quantity of cement = (Own Ratio/ Total sum of ratio) * Dry Volume = ( 1/10 ) * 1.54 =  0.154 m³ Cement in kg = volume of cement * density of cement = 0.154 * 1440 = 221.76 kg  

ii. Sand Quantity Calculation 

Quantity of sand = (Own Ratio/ Total sum of ratio) * Dry Volume = ( 3/10 ) * 1.54 =  0.462 m³  

iii. Aggregate Quantity Calculation 

Quantity of aggregate = (Own Ratio/ Total sum of ratio) * Dry Volume = ( 6/10 ) * 1.54 =  0.924 m³  

iv. Water Calculation

For inferior-quality concrete: W/C ratio = 0.60 For superior-quality concrete: W/C ratio = 0.55 Minimum amount of water required per m³ = 0.55 * 221.76 = 121.968 kg  Maximum amount of water required per m³ = 0.60 * 221.76 = 133.056 kg

( 1 kg of water is equivalent to 1 L of water.)  

  4. References  

1. IS 10262 (2009): Code 

 

Read Also: Grades of Concrete
Verified Article By Er. Madhu Krishna Poudel
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Madhu Krishna Poudel
Madhu Krishna Poudel
Madhu Krishna Poudel is a civil engineering technician and field practitioner with 8+ years of hands-on experience in construction. He is the founder of DreamCivil.com and holds a Bachelor's degree in Civil Engineering. Over his career, he has planned and drafted 100+ structures, supervised construction on 200+ sites, and taught civil engineering students, with core expertise in site supervision, construction estimation, and AutoCAD 2D/3D design. His technical content has been cited as a reference by globally recognized platforms including Wikipedia, Time Magazine, TheRichest, and WSWS.
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