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M20 concrete ratio is 1:1.5:3. It indicates the cement:sand: aggregate ratio. It simply means that if 1 kg cement is used for making Concrete, you should use 1.5 kg sand and 3 kg aggregate. ( i.e. 1 part cement: 1.5 parts sand: 3 parts aggregate )
✔ In M20 concrete,
“M” stands for Mix ratio of cement:sand: aggregate & “20 “Stands for Compressive Strength @ 28 Days in N/mm².
✔ M20 Concrete is nominal Concrete that can be skillfully prepared using Indian Standard IS 456:2000.
✔ Normally, about 38% of water is required for the complete hydration of Concrete.
As per Indian Standard IS 456:2000 for nominal mix ( i.e., M10, M15…, M25), the w/c ratio varies from 0.4 to 0.6.
For M20 Concrete, commonly w/c ratio of 0.45 to 0.50 is used.
1. Table1: M20 Concrete Ratio – Overview
Code  Indian Standard 10262(2009). 
Ratio  1:1.5:3 
Compressive Strength  20 MPa { Note: MPa = N/mm²} 
Uses  Used in RCC works like;
a. Rigid Pavement Construction b. Used to construct structural members like slabs, beams, columns, etc. (for small to medium structures only. Not suitable for heavy structures or work). c. Water retaining structures, piles, etc. 
Grade Category  Normal Grade ( Nominal Mix ) 
Required Water Cement Ratio 
a. For highquality concrete works; 0.45 w/c ratio is specified. b. Minimum watercement ratio: 0.45 c. Maximum watercement ratio: 0.50

2. M20 Concrete Ratio Uses
This concrete grade is commonly used for small to mediumscale constructions. Some common uses of the M20 Concrete Ratio are:
✔ Used in the construction of water retaining structures.
✔ Used to construct piles and other general RCC structures.
✔ Used to build retaining walls, buildings, landscaping & architectural designs, etc.
3. Cement Sand Aggregate Calculation For 1 m³ M20 Concrete Ratio
Data per 1 m³ of M20 Concrete Ratio
Material  Volume Required (m^{3})  Materials Required in kg 
Cement  0.28  403.2 
Fine Aggregate  0.42  619.85 
Coarse Aggregate  0.84  1359.82 
Water  0.190  190 kg ( Average ) 
Things To Know!!
Density of Cement = 1440 kg/m^{3} Density of Sand = 14501500 Kg/m^{3} Density of Aggregate = 14501550 Kg/m^{3} Weight of Cement in 1 Bag = 50 Kg Volume of 1 Bag of Cement in Cubic meter = 0.03472 m^{3} 
Now, Taking
Grade of Concrete = M20 Concrete
Mix Ratio = 1:1.5:3
Total sum of ratio =1+1.5+3 =5.5
Wet volume of Concrete = 1 m^{3}.
To get dry volume, wet volume increased by 54%
Dry volume of concrete = 1 + 0.54 = 1.54 m³
i. Cement Quantity Calculation
Quantity of cement = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 1/5.5 ) * 1.54
= 0.28 m³
Cement in kg = volume of cement * density of cement
= 0.28 * 1440
= 403.2 kg
ii. Sand Quantity Calculation
Quantity of sand = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 1.5/5.5 ) * 1.54
= 0.42 m³
iii. Aggregate Quantity Calculation
Quantity of aggregate = (Own Ratio/ Total sum of ratio) * Dry Volume
= ( 3/5.5 ) * 1.54
= 0.84 m³
iv. Water Calculation
For inferiorquality concrete: W/C ratio = 0.5
For superiorquality concrete: W/C ratio = 0.45
Minimum amount of water required per m³ = 0.45 * 403.2 = 181.44 kg
Maximum amount of water required per m³ = 0.5 * 403.2 = 201.6 kg
4. References 
Read Also: Grades of Concrete 
Verified Article By Er. Madhu Krishna Poudel 